MELBOURNE, AUSTRALIA—Canadian Milos Raonic is moving on to the fourth round of the Australian Open for the sixth time in his career.
Raonic earned his way into the Round of 16 on Saturday by beating France’s Pierre-Hugues Herbert in straight sets.
The Thornhill, Ont., product, ranked 17th in the world, downed No. 53 Herbert: 6-4, 6-4, 7-6 (6).
Raonic swept to 3-0 and 5-1 leads in the tiebreaker but Herbert rallied to level at 5-5. Herbert saved one match point before Raonic clinched the 2-hour, 1-minute match with an ace.
Raonic will play the winner of the later match between fourth-seeded Alexander Zverev and Alex Bolt.